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Hello Team,
Good day!
I would like create the random number on basis selected answer of previous question and then only top 3 will selected form that list

For example
I have a question Q1(Multiple choice) having answer option A,B,C,D,E,F,G,H,I AND i have selected option A,C,D,F,G,H,I, for another question Q2(Multiple choice) having same option as Q1 but i need to show the only top 3 option by randomly from Q1

 

Sounds tricky!
I think a solution can be to use array filter feature to only show the selected items at Q2.
Q2 should be set to be ordered randomly.
You can then apply some custom JS to remove all items after the top three.

I aware of the array filter that will show only the selected answer in previous selected answer
But my concern is it will show the randomly only top 3
Can you help on this by custom java script

What are the "top 3" in a multiple question?
Or only 3 randomly selected from all selections?
For the second there are many examples in the forum, only using ExpressionScript with the idea:
1.
​​​​​​Create a string with symbols of the selected options like "BDEGI"
2. Create a random number from 1 to the length of this string.
3. Capture the letter at this position
4. Remove the letter from the string.
5. Start again at 2. now with the shorter string

Stop after you captured three letters.
Now you have your thrree randomly selected options 
Display the options that are represented by the letters with " conditions".

Search the forum for a more detailed description and a sample.
I am sure there is.

​​​​​​

Thanks you for response
For the second i had the java script for the same
<script type="text/javascript" charset="utf-8">
    
    var numberToShow = 5;
    
    $(document).on('ready', function(){      
        if($('#question{QID} input:checkbox:checked').length == 0) {
            $('#question{QID} input:checkbox:lt('+numberToShow+')').each(function(i) {
                $(this).nextAll('input:hidden').val('Y');
                $(this).prop('checked', true).trigger('change');
            }); 
        }
    });
</script>
But my requirement something different i will show the 3 answer option randomly on the basis previous questions selected answer 
Let us suppose i have Q1 have 10 option but i selected the 6 option, from this 6 selected option we need to show only 3 option in the next question on random basis
I hope you understood my requierment

@joffm, that letter-based approach sounds pretty interesting. But how can you loop through this using EM?
E.g. once the first character was picked, how can you pass the updated letters to a second call of that function?

@Mazi,
at the moment I'm on vacation.
When I'm back in Germany I show/send a full example.

@rajkumar_dms, yes we understood your wish.
You have solution with pure ExpressionScript.

javascript is also possible.
Store the "string" in a question of type "short text".
Change the string to an array, shuffle the array, and use the first three elements. 

 

Hi,

Can you share the example for the same as per my wish

What part of "He is on vacation and he will share it when he is back in Germany" did you not understand?

This is a forum where users help users. There is no right for a (quick) answer. Please be patient.

Hi Holch,
Thanks for reply
Sorry for inconvenience
I doesn't mean for quick response,i just follow up the same
I thought he came back from vacation

Hi,
Let's say the first multiple question is Q1 with subquestion codes 1, 2, 3, ...
To do this I prefer to create a "container" to store interim results
1. Create a question of type "multiple short text" (I called it "RC" like "Result Container") with subquestions
RC_11
RC_12
RC_13
RC_21
RC_22
RC_23
RC_31
RC_32
RC_33
RC_99 (for the final result)
Three subquestions are needed for each element

2. Create a question of type "equation" and enter (only) the equations
First create the base:
{RC_11=join(if(Q1_1=="Y","A",""),if(Q1_2=="Y","B",""),if(Q1_3=="Y","C",""),if(Q1_4=="Y","D",""),if(Q1_5=="Y","E",""),if(Q1_6=="Y","F",""),if(Q1_7=="Y","G",""),if(Q1_8=="Y","H",""),if(Q1_9=="Y","I",""),if(Q1_10=="Y","J",""))}
We get something like "ADEGIJ"
Now the procedure I explained before
Random number from 1 to the length of this string
{RC_12=if(is_empty(RC_12),rand(1,strlen(RC_11)),RC_12)}

Capture the letter at this position
{RC_13=substr(RC_11,RC_12-1,1)}

Remove the letter at this position; this is the base for the next round
{RC_21=str_replace(RC_13,'',RC_11)}
{RC_22=if(is_empty(RC_22),rand(1,strlen(RC_21)),RC_22)}
{RC_23=substr(RC_21,RC_22-1,1)}

{RC_31=str_replace(RC_23,'',RC_21)}
{RC_32=if(is_empty(RC_32),rand(1,strlen(RC_31)),RC_32)}
{RC_33=substr(RC_31,RC_32-1,1)}

Now there are three letters (in RC_13, RC_23 and RC_33)

Joined with a  '#' (important for the function "strpos(x,y)")
{RC_99=join('#',RC_13,RC_23,RC_33)}

Now the conditions of the subquestions in Q2 are (just ask: Does the final strinf contain the letter)
strpos(RC_99,"A")>0
strpos(RC_99,"B")>0
strpos(RC_99,"C")>0
...


And there is this javascript solution.
Create a question of type "short text"
in the default answer enter
{list(if(Q1_1=="Y","A",""),if(Q1_2=="Y","B",""),if(Q1_3=="Y","C",""),if(Q1_4=="Y","D",""),if(Q1_5=="Y","E",""),if(Q1_6=="Y","F",""),if(Q1_7=="Y","G",""),if(Q1_8=="Y","H",""),if(Q1_9=="Y","I",""),if(Q1_10=="Y","J",""))}

and this script


Hide the question with css class "d-none"
and use the same subquestion conditions.

Joffm