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==================Hello team,

I would like to conduct a survey using LimeSurvey.The study concerns news framing effects. For this reason, two experimental conditions have been designed, in which participants will be exposed to a message about the European Union at the beginning of the questionnaire. There is also a control group, in which participants will not be asked to read any message. Each participant will answer only one questionnaire. Therefore, there are three different questionnaires: two questionnaires that include a message at the beginning, and one control-group questionnaire without a message at the beginning. The message at the beginning is the only difference between the two questionnaires. Everything else is identical. The control group includes exactly the same questions as the other two groups, except for two manipulation-check questions included in the two treatment conditions.My question is how random allocation of participants to one of the three conditions can be implemented in LimeSurvey.Thank you very much in advance for your time and assistance.Kind regards,
Evangelos Theodorou

Hi,
you have to create a random number from 1-3.
Then you show the first message if this random number is equal 1, the second if the number is equal 2.
This is done in the field "condition" of this question.

The same you do with your two manipulation checks.

A random number is created in a question of type "equation". Let's call it "randnum"
In the manual, chapter about "implemented functions", you find the function "rand(x,y)".
To avoid a later change of the generated number (the same behaviour as Excel) we usually use this construct
{if(is_empty(self),rand(1,3),self)}
About the variable "self" please read the manual.

Now you enter in the "condition" of the first message randnum==1, and in the second randnum==2

If there are further questions about this, please send the lss Export of the survey.

Joffm

BTW: Why didn't you answer the questions that appeared at the beginning?