Hi guys,

I have a question (Q1) where the respondent must select from a multiple choice question. If they select more than 1 choice, we want to ask them what their main choice is in the following question (Q2). If they only answer with 1 choice at Q1, then we want to auto-fill Q2 and hide it from the user. This is so the user doesn't see Q2 with the array filter showing only a single option.

Unfortunately, it seems to work if Q2 is hidden all the time, however, if I duplicate Q2 as Q3 and add routing (Answer Count @ Q1 > 1) then the answer does not get pre-filled anymore.

 

LS: Version 3.17.16+190906

Goal: Get Q3 to record data in the responses when only 1 option selected at Q1.

You need 2 question : one hidden and one hidden by relevance.

relevance for answer to be null.

Apologies Denis - I'm not 100% sure what you mean.

Are you suggesting that I should have 2 "copies" of the question? Ideally I would like the data to be contained within a single question as I need to use the answer given later in the survey.

Yes :

Q2shown : relevance count(that.Q1.NAOK) > 1
Q2: equation with {if(count(that.Q1.NAOK) > 1),Q2shown.NAOK,list(Q1.NAOK))}

The relebvance force Q2 ro be null, then you can not use it if you hide it.

Thanks Denis - was not aware it would force Q2 to be null.

I can see the logic in the equation you provided, however I think it would not be usable as the value returned by `list(that.Q1.NAOK)` would be "Y". We would have no context for what subquestion this relates to. I'm not sure if there is a way to return the subquestion code rather than the value of the checkbox for multiple choice questions.

I have managed to get it working using the logic of having a Q2shown and a Q2hidden however, with an equation to set the value:

`Q2Hidden=if((count(that.Q1.NAOK) == 1) && Q1_1 == "Y", 1, if((count(that.Q1.NAOK) == 1) && Q1_2 == "Y", 2, if((count(that.Q1.NAOK) == 1) && Q1_3 == "Y", 3, Q2Shown)))`

Arg you right about list(that.Q1) …

About your system, i prefer to use join/concat since if count(that.Q1.NAOK) == 1 it can be ony one choice …

{join(
if((count(that.Q1.NAOK) == 1) && Q1_1 == "Y", 1),
if((count(that.Q1.NAOK) == 1) && Q1_2 == "Y", 2),
…
if((count(that.Q1.NAOK) > 1), Q2.NAOK)
)}

Else : warning with 1,2 … 10,11 etc …
I always prefer to have 01,02,03 … 10,11