And there is an one-equation solution.
If you consider that there are only 6 (4 over 2) different combinations
1-2, 1-3, 1-4, 2-3, 2-4, 3-4
one random number between 1 and 6 is sufficient
And the questions than get the relevance equations:
Q1: random < 4
Q2: random==1 or random==4 or random==5
Q3: random==2 or random==4 or random==6
Q4: random=

or random>4
This is to show that remembering a bit of mathematics at school some things may become easy.
Joffm
PS.
Of course I know that this gets very complicated when trying to select 3 out of 10. (10 over 3 = 120)