Hi, a have 3 sets of 5 groups containing questions. Can I add a page to show the partial results between each set?
So you would complete the first 5 groups then have a page showing results (i.e. how many right answers you gave) then move on the following group.

Thanks

Why not.
Question of type "text display".
Enter results by Expression Manager.

Joffm

thanks! where do I find examples of using the expression manager for such thing?

In the manual there are several sections that explain the expression manager and there are loads of examples, even with LSS downloads so you can have a look at the examples in a real survey.
www.limesurvey.org/manual/ExpressionScript_-_Presentation
www.limesurvey.org/manual/Expression_Manager
www.limesurvey.org/manual/Expression_Manager_sample_surveys

Thanks I've managed to do it with the following:

<p>You got: {sum(if(INSERTANS:926488X746X2301==1,1,0), if(INSERTANS:926488X741X2291==1,1,0), if(INSERTANS:926488X736X2281==1,1,0), if(INSERTANS:926488X725X2260==2,1,0), if(INSERTANS:926488X730X2270==2,1,0), if(INSERTANS:926488X721X2252==2,1,0))} / 6 correct answers in this set.</p>

I'm now trying to end the survey if that value is below a certain number. Can I also do that with expression manager? I'm not sure how to refer to the 'end' of the survey.
Thanks

There are two interpretations of what you want to do:
1. You want to screen people out --> Quota, more specifically "Zero quota". The will not make it to the end page of your survey, but rather get an alternative end.
2. You do not want to screen them out, but send the respondents to the end page. Then you will need to use relevance equations (either on a group or a question level) to hide all following questions until the end page.

By the way:
Your
{sum(if(INSERTANS:926488X746X2301==1,1,0), if(INSERTANS:926488X741X2291==1,1,0), if(INSERTANS:926488X736X2281==1,1,0), if(INSERTANS:926488X725X2260==2,1,0), if(INSERTANS:926488X730X2270==2,1,0), if(INSERTANS:926488X721X2252==2,1,0))}

can be shortened to
(and do not use these INSERTANS stuff; use the question code. It is much easier to read)
{sum(countif("1",Q1.NAOK,Q2.NAOK,Q3.NAOK),countif("2",Q4.NAOK,Q5.NAOK,Q6.NAOK))}

@holch already showed the links to Expression Manager.

Joffm

Hi the formula with countif doesn't seem to be working.
Assuming question codes are "q1", "q2"..."q6"

You got: {sum(if(INSERTANS:774328X936X2664==1,1,0), if(INSERTANS:774328X939X2670==1,1,0), if(INSERTANS:774328X940X2672==1,1,0), if(INSERTANS:774328X937X2666==2,1,0), if(INSERTANS:774328X938X2668==2,1,0), if(INSERTANS:774328X941X2674==2,1,0))} / 6 correct answers in this set.


test:{sum(countif("1",q1.NAOK,q4.NAOK,q5.NAOK),countif("2",q2.NAOK,q3.NAOK,q6.NAOK))}

the second formula always returns 0